For a typical house requires 235 W of electric power on average, deuterium fuel used is mathematically given as
E=79206.75
How much deuterium fuel would have to be used in a year to supply these electrical needs?
Generally, the mass and time statement of deuterium is mathematically given as
Mass deuterium=2.014g
time =3.15*107s= 1year
In conclusion, energy
E=235*3.15*107s
E=79206.75
Read more about Electric
https://brainly.com/question/9383604
