a. Area of the exposed water of the prism pool: 33.5 ft²
b. The area of exposed water for the cone pool = 102.1 ft²
c. Hemisphere pool = πr² = π(4²) = 50.3 ft²
Volume = (2/3)πr
Volume = 1/3πr²h
Volume = Base area × height
a. Area of the exposed water = area of the square top = base area of the prism
Find base area using, Volume = Base area × height. Thus:
134 = Base area × 4
Base area = 134/4 = 33.5 ft²
Area of the exposed water for the prism pool = 33.5 ft²
b. Find the radius of the cone using, volume = 1/3πr²h.
134 = 1/3πr²(4)
(3)(134) = πr²(4)
402/4π = r²
32 = r²
r = 5.7 ft
The area of exposed water for the inverted cone pool = πr² = π(5.7)² = 102.1 ft²
c. The radius is the depth of the hemisphere pool
The area of the exposed water for the hemisphere pool = πr² = π(4²) = 50.3 ft²
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