The mean of the sampling proportion is 0.03 and the standard deviation of the sampling proportion is 0.008 if the probability that a student forgets to bring their ID with them when they take their SAT is 3%. and a random sample of 500 students was selected.
It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.
We have:
p = 0.03
n = 500 students
[tex]\rm {\hat p} - Normal[/tex]
So the mean:
[tex]\rm \mu _\hat p \ = \ p \ = \ 0.03[/tex]
For standard deviation:
[tex]\rm \sigma_p = \sqrt{\frac{pq}{m} }[/tex]
q = 1 - p = 1 - 0.03 = 0.97
[tex]\rm \sigma_p = \sqrt{\frac{0.03\times 0.97}{500} }[/tex]
[tex]\rm \sigma_p = 0.008[/tex]
Thus, the mean of the sampling proportion is 0.03 and the standard deviation of the sampling proportion is 0.008 if the probability that a student forgets to bring their ID with them when they take their SAT is 3%. and a random sample of 500 students was selected.
Learn more about the standard deviation here:
brainly.com/question/12402189
#SPJ1