PLEASE HELP!!!

BRAINLIEST TO CORRECT ANSWER!!!

The teacher wants to figure out the relative frequency of a student choosing the aquarium. He will then estimate how many students out of all 1000 at the school are likely to choose the aquarium.

Answer the questions to solve the problem.


1: How many students did the teacher survey?

2: What is the Relative Frequency of a student choosing the aquarium?
(Give answer as a decimal rounded to the nearest hundredth - Show your work)

3: The teacher surveys one student at random. Based on the survey results, what is the estimated probability that the student will choose the aquarium?

4: Write and solve a proportion that the teacher can use to estimate how many students in the WHOLE school would choose the aquarium. (Show your work)

PLEASE HURRY!!!!​

PLEASE HELPBRAINLIEST TO CORRECT ANSWERThe teacher wants to figure out the relative frequency of a student choosing the aquarium He will then estimate how many class=

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Answer:

See below ~

Step-by-step explanation:

Q1

  • Number of students surveyed = 80 + 60 + 30 + 40
  • Number of students surveyed = 140 + 70
  • Number of students surveyed = 210

Q2

  • Relative Frequency (aquarium) = 80/210 = 8/21
  • Relative Frequency (aquarium) = 0.38

Q3

  • P (aquarium) = 80/210 = 8/21
  • P (aquarium) = 38.1%

Q4

  • Let x be the number of students in the whole school who would choose the aquarium. Then, the proportion would be :
  • x/1000 = 8/21
  • x = 8000/21
  • x = 381 students (nearest whole number)