13 A right-angled triangle is formed by the diameters of three semicircular regions, A, B and C
as shown in the diagram.
B
Show that
area of region A-area of region B+ area of region C

13 A rightangled triangle is formed by the diameters of three semicircular regions A B and C as shown in the diagram B Show that area of region Aarea of region class=

Respuesta :

Answer:

Region C Area = [tex]\pi (\frac{c}{2} )^{2} = \frac{\pi c^{2} }{8} \\[/tex]

Region B Area = [tex]\pi (\frac{b}{2})^2 = \frac{\pi b^2}{8}[/tex]

Region A Area = [tex]\pi (\frac{a}{2})^2 = \frac{\pi a^2}{8}[/tex]

[tex]\frac{\pi c^2}{8} + \frac{\pi b^2}{8} = \frac{\pi a^2}{8}[/tex]

(Now divide the whole equation by 8):

[tex]\pi c^2 + \pi b^2 = \pi a^2[/tex]

(Now divide the whole equation by [tex]\pi[/tex]):

[tex]c^2 + b^2 = a^2[/tex]

This is what I have got up until but I don't know if that answers the actual question.

Hope it helps.