Respuesta :
[tex]\bold{\huge{\underline{ Solution }}}[/tex]
Given :-
- Meena mother is 4 times as old as Meena
- After 5 years, Her mother will be 3 times as old as she will be then.
To Find :-
- We have to find the present ages of Meena and her mother.
Let's Begin :-
Let the present age of Meena be ' x ' years.
- Now, It is given in the question that her mother is 4 times as old as Meena
That means,
Present age of her mother
[tex]\sf{ = 4x \: years }[/tex]
Now,
After 5 years
The age of the Meena will be
[tex]\sf{ = x + 5 \: years }[/tex]
Therefore,
According to given condition,
The age of her mother will be
= [tex]\sf{ = 4x + 5 \: years ...eq(1)}[/tex]
But, It is given that,
- After 5 years, Her mother will be 3 times as old as Meena.
That is,
After 5 years, Her mother age will be
[tex]\sf{ = 3(x + 5) \: years ...eq(2)}[/tex]
From eq(1) and (2) :-
[tex]\sf{ 4x + 5 = 3(x + 5) }[/tex]
[tex]\sf{ 4x + 5 = 3x + 15}[/tex]
[tex]\sf{ 4x - 3x = 15 - 5 }[/tex]
[tex]\sf{ x = 10 \: years }[/tex]
Thus, The present age of the Meena will be 10 years.
Therefore,
The present age of her mother will be
[tex]\sf{ 4x = 4 × 10 }[/tex]
[tex]\sf{ = 40 \: years }[/tex]
Hence, The present of Meena and her mother is 10 years and 40 years.