Respuesta :
Given:
length= 15 cm
width= 7 cm
To find:
The area of the given rectangle.
Solution:
[tex]a = wl[/tex]
[tex]a = 15 \times 7[/tex]
[tex]a = 105 \: {cm}^{2} [/tex]
Therefore, the area of the given rectangle is 105 square centimeters.
Question :-
- Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .
Answer :-
- Area of Rectangle is 105 cm² .
[tex] \rule {195pt} {2pt} [/tex]
Diagram :-
[tex] \sf{15 \: cm} \\ \quad \quad \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\ \\ \\ \end{array}} \: \: \sf {7 \: cm}\end{gathered}\end{gathered} [/tex]
[tex] \rule {195pt} {2pt} [/tex]
Solution :-
[tex] \quad \quad [/tex] » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.
For calculating the Area of Rectangle , we will use the Formula :-
- [tex] \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\ [/tex]
[tex] \Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7} [/tex]
[tex] \Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105} [/tex]
Hence :-
- Area of Rectangle = 105 cm² .
[tex] \underline {\rule {195pt} {4pt}} [/tex]
Additional Information :-
[tex] \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} [/tex]