Answer:
761680
Explanation:
[tex]\sf \boxed{\sum _{n=1}^{44}\:60\left(1.2\right)^{n-2}}[/tex]
Identify the following's:
First Term [a] = 60(1.2)ⁿ⁻² = 60(1.2)¹⁻² = 50
Common ratio [r] = 1.2
Total Terms [n] = 44
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[tex]\sf Geometric \ Sum \ of \ Terms = \dfrac{a(r^n - 1)}{r-1}[/tex]
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Solving Steps:
[tex]\rightarrow \sf \dfrac{a(r^n - 1)}{r-1}[/tex]
[tex]\rightarrow \sf \dfrac{50(1.2^{44} - 1)}{1.2-1}[/tex]
[tex]\rightarrow \sf 761679.5808[/tex]
[tex]\rightarrow \sf 761680 \ \ \ (rounded \ to \ nearest \ integer)[/tex]
