Answer:
Question 1: The larger cup will hold around 6 in more water. Just enter 6.
Question 2: The answer will be the second option " The rectangular prism holds 41.6 in^3 more than the cylinder"
i used the pi sign in my calculation thats why my answer was slightly off but its basically the same so dw.
Step-by-step explanation: 1:
Question 1: Find the volume of both cups then compare and contrast.
Volume of 1st cup:
Since the cup is made up of 2 cylinders we can find the volume of each and then add them together
Volume of Bottom half of cup: [tex]V=\pi r^{2} h[/tex]
[tex]V=\pi( 2^{2}) (2.25)[/tex]
[tex]V=28.27 in^{3}[/tex]
Volume of Top half of cup: [tex]V=\pi r^{2} h[/tex]
[tex]V=\pi( 3^{2}) (1.5)[/tex]
[tex]V=42.41in^{3}[/tex]
Total volume of cup = 28.27 + 42.41
= 70.68 in^3
Volume of 2nd Cup : [tex]V=\pi r^{2} \frac{h}{3}[/tex]
[tex]V=\pi (3.5^{2} )(\frac{6}{3} )[/tex]
[tex]V= 76.97 in^{3}[/tex]
Now we can see that the second cup (the triangular cone) is larger and to see how much larger, we simply subtract the volumes of each cup:
76.97-70.68 = 6.29
The second cup is larger by 6.29in
Question 2: Find the volume of each cup then compare and contrast:
Volume of 1st cup:
Volume of cylindrical cup = [tex]V=\pi r^{2} h[/tex]
[tex]V=\pi( 4^{2})( 10)[/tex]
[tex]V=502.65 in^{3}[/tex]
Volume of 2nd container: [tex]V=whl[/tex]
[tex]V=(8)(8.5)(8)[/tex]
[tex]V=544in^{3}[/tex]
Now subtract: 544 - 502.65 = 41.35
