The value of b in the quadratic equation ax² + bx + c is 11.
How to find the value of b in a quadratic equation?
The value of b can be found as follows in the quadratic equation.
ax² + bx + c
(-2, -9)(-1, -1)(0, 9)
Therefore,
9 = a(0)² + b(0) + c
c = 9
Therefore,
-1 = a(-1)² + b(-1) + c
-1 = a - b + 9
-1 - 9 = a - b
a - b = - 10
using (-2, -9)
-9 = a(-2)² + b(-2) + 9
-9 - 9 = 4a - 2b
-18 = 4a - 2b
2a - b = -9
combine the equation
a - b = - 10
2a - b = -9
a = 1
Then,
1 - b = -10
b = 1 + 10
b = 11
Therefore, the value of b is 11.
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