The angle of depression of the airplane is 39.8°, length of the runway is 45794 ft, and approximate height of the tower is 321 m.
What is the angle of depression of the airplane?
The angle of depression of the airplane is given as follows:
Let the angle of depression be A.
[tex]A= {tan}^{ - 1} ( \frac{15000}{8000} ) = {39.8}^{o} [/tex]
Angle of depression is 39.8°.
If the angle of elevation is 6.8°, the length of the runway l is calculated thus:
horizontal distance of airplane from end of runway = d
length of runway, L = d - 80000 ft
[tex]d = \frac{15000}{tan 6.8°} = 125794 ft[/tex]
L = 125794 - 80000
L = 45794 ft
The length of the runway is 45794 ft
2. Let the height of the tower be H
[tex]H = \tan(69.8) \times 118 = 321m[/tex]
The approximate height of the tower is 321 m
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