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Here is a growing pattern of squares:
Step 1
Step 2
Step 3
Select all the definitions that represent the number of squares in Step n.
f(n) = 3n+ 5 for n > 1
f(n)=3+8(n-1) for n > 1
f(1) = 8, f(n)=3+ f(n-1) for n > 2
f(1) = 8. f(n) = 8 + f(n-1)for n > 2
f(n)=8+3 (n-1) for n > 1
f(n)=3+ 8n for n > 1

Here is a growing pattern of squares Step 1 Step 2 Step 3 Select all the definitions that represent the number of squares in Step n fn 3n 5 for n gt 1 fn38n1 fo class=

Respuesta :

TOKYOGHOULKENKANEKI

Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

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