The equation that represents a quadratic function written in vertex with a vertex of (3,5) and passes through the point (1, 13) is y = 2(x - 3)^2 + 5
The given parameters are:
A quadratic equation is represented as:
y = a(x - h)^2 + k
So, we have:
y = a(x - 3)^2 + 5
Substitute (x,y) = (1,13) in the equation
13 = a(1 - 3)^2 + 5
Evaluate the exponent
13 = 4a + 5
Subtract 5 from both sides
4a = 8
Divide both sides by 4
a = 2
Substitute a = 2 in y = a(x - 3)^2 + 5
y = 2(x - 3)^2 + 5
Hence, the equation of the quadratic function is y = 2(x - 3)^2 + 5
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