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Find the minimum point(s) of f(x) = x - 2x² + 1 given that f'(x) = 4x³ - 4x.​

Respuesta :

Answer: f(x) = x - 2x² + 1

              x=-b/2a

              (1/4,9/8

   2.      f'(x) = 4x³ - 4x

            ((\sqrt(3))/(3),-(8\sqrt(3))/(9))is a local minima

             (-(\sqrt(3))/(3),(8\sqrt(3))/(9))is a local maxima

                     

Step-by-step explanation: hopes this help

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