The concentration of chlorine gas in air must be reduced from 10. 0 mg/m³ to 2. 95 mg/m³. Determine the height of the absorption packed tower that should be used if the following parameters

Respuesta :

The height of the absorption packed tower that should be used is  1.84m.

What is density?

The density is the ratio of mass and volume of the matter.

The mole fraction of pollutant in gas phase at inlet, y₁ = (ρCl₂/GMW of Cl₂)/(ρair/ GMW of air)

GMW of air is 28.97, GMW of Cl₂ is 70.096, density of air is 1.205 kg/m³ and density of Cl₂ is 10mg/m³ x 10⁻⁶ kg/mg

Substitute the value, we get the mole fraction at inlet,

y₁ =3.391 x 10⁻⁶

The mole fraction at outlet where density of chlorine is 2.95 x 10⁻⁶ kg/m³ is

y₂ =1 x 10⁻⁶

Value of A =m Qg/Ql

Qg  is the gas flow rate and Ql is the liquid flow rate, m is Henry's constant

A = 6.82 x (3/28.97GMW of air) / (15/18.05GMW of H₂O)

A=0.848203

Number of gas transfer unit, Nog ={ ln[y₁ -mx₂/y₂ -mx₂](1-A) +A} / (1-A)

Substitute the values, we get

Nog = 2.039

The height of an individual gas transfer unit, Hog = Hg +A.Hl

Substitute Hg =0.662 and Hl = 0.285. we get

Hog =0.9037m

Height of packed tower, Z = Hog x Nog

Substitute the value, we get

Z= 1.84m

Thus, the height of the absorption packed tower is 1.84m.

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