The balanced redox reaction, if it occurs in acidic solution, is
5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺-----> 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l)
Redox reactions are those in which loss and again of electrons occur.
To balance the redox reaction, we must first break the whole reaction into half equations;
Oxidation half equation
[tex]\rm 5C_2O4^2^-(aq) + 10e + 8H^+----- > 10CO_2(g) + 4H_2O(l)[/tex]
Reduction half equation
[tex]\rm 2MnO_4^- (aq) + 10e + 8H^+----- > 2Mn^2+(aq) + 4H_2O(l)[/tex]
Now combine both the reactions
[tex]\rm 5C_2O_4^2-(aq) + 2MnO4^- (aq) + 16H^+----- > 10CO_2(g) + 2Mn^2+(aq) + 8H_2O(l)[/tex]
Thus, the coefficient of H₂C₂O₄ is 5 and that of water is 8.
Learn more about redox reactions
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