Respuesta :
The acceleration of the charge is 1.07 × 10²⁸ m/s². It is obtained as the force per unit mass of the charge.
What is Columb's law?
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm F = \frac{Kq_1q_2}{r^2} \\\\ F= \frac{9 \times 10^9 \times( 3.2 \times 10^{-19})^2}{(3.60 \times 10^{-15})^2}\\\\ F=71.1 \ N[/tex]
The acceleration of the charge is found as;
[tex]\rm a = \frac{F}{m} \\\\ \rm a = \frac{71.1}{4.0026 \TIMES 1.66 \TIMES 10^{-27}} \\\\ a=1.07 \times 10^{28} \ m/s^2[/tex]
Hence,the acceleration of the charge is 1.07 × 10²⁸ m/s².
To learn more about Columb's law, refer to the link;
brainly.com/question/1616890
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