The impedance of the circuit will be 469 ohms. It is obtained by its specified formula.
The combined effect of resistance and reactance in a circuit creates impedance, which opposes alternating current.
The given data is;
R=206 Ω
L=0.875 H
C=6.25 μF
E= 30.5 V
ω=250 rad/sec
The inductance is found as;
[tex]\rm X_L= \omega L \\\\ X_L= 250 \times 0.875 \\\\X_L=640 \ ohm[/tex]
The capacitance is found as;
[tex]\rm X_C = \frac{1}{\omega_C} \\\\ \rm X_C = \frac{1}{ 250 \times 6.25 \times 10^{-6}} \\\\ X_C =640 \ ohm[/tex]
The impedance of the circuit is found as;
[tex]\rm Z= \sqrt{R^2+(X_L-X_C)^2} \\\\\rm Z= \sqrt{(2.6^2)(218.75-640)^2} \\\\ Z=469 \ ohm[/tex]
Hence,the impedance of the circuit will be 469 ohms.
To learn more about the impedance, refer to the link;
https://brainly.in/question/12433840
