If each of the charges double,the electric force will be four times the previous case.
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm F= \frac{Kq_1q_2}{R^2} \\\\ F'= \frac{K(2q_1\times 2q_2)}{R^2} \\\\ F'=4 \frac{Kq_1q_2}{R^2}\\\\ F'=4F[/tex]
Hence,if each of the charges double,the electric force will be four times the previous case.
To learn more about Columb's law, refer to the link;
brainly.com/question/1616890
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