The points p(3, –2), q(10, –2), and r(3, –8) are the vertices of a triangle, then, The length of the side RQ will be 9.22 units.
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]
The length of side RQ will be,
[tex]\rm Length = \sqrt{(3-10)^2+(-8-(-2))^2}\\\\Length=\sqrt{49+36}\\\\Length = \sqrt85\\\\Length = 9.22[/tex]
Hence, the length of the side RQ will be 9.22 units.
Learn more about the Distance between two points:
brainly.com/question/16410393
#SPJ4