Respuesta :
Answer:
Mass=50.0g
H=670J
change in temperature=40
using. c=h÷m×change in temperature
c=670÷50×40
C=670÷2000
C=0.335jkg-1k-1
Answer: The specific heat of a substance with a mass of 50. 0g and a temperature change of 40. 0 degrees whne it absorbs 670 J of heat is 337 J/kg. K
Explanation:
Specific heat of a substance is said to be the energy required for an increase in temperature by 1°C in the unit of J/Kg. K
Formula of Specific heat:
Q = mcΔθ
Q represents the quantity of heat
m represents the mass of the substance in Kilograms = 50. 0g÷ 1000 = 0.05kg
c represents the specific heat capacity of the substance = ?
θ represents the temperature change = 40° C
Specific heat, c = Q ÷ mΔθ
= 670 ÷ 0.05 × 40
= 670 ÷ 2
= 335 J/ Kg. K
Therefore, the specific heat of the substance is 335 J/kg. K
