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Two small metal spheres are 35. 1 cm apart. The spheres have equal amounts of negative charge and repel each other with forces of magnitude 0. 0360 n. The charge on each sphere [tex]Q = 1.4 \times 10^{-12}[/tex] c.
What is coulombs law?
According to coulombs law force between two charges is given by
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}[/tex]
Here, R is the distance between both the charges Q and q.
Two small metal spheres are 35. 1 cm apart.
The spheres have equal amounts of negative charge and repel each other with forces of magnitude 0. 0360 n.
We have given force F =0.036 N
R is the distance between both the charges which is given as 25 cm
So
[tex]F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}[/tex]
[tex]0.036 = \dfrac{1}{4\times 3.14\times 8.85\times 10^{-12} }(\dfrac{Q^2}{35. 1})[/tex]
[tex]Q = 1.4 \times 10^{-12}[/tex] c
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