Respuesta :
Maxwell's relations are a set of thermodynamic equations. The value of g is -65.246 j Mol⁻¹.
What is Maxwell Relation?
Maxwell's relations are a set of thermodynamic equations derived from the symmetry of second derivatives and the definitions of thermodynamic potentials.
At -3°C the pressure of ice vapour is 475 Pa and subcooled water is 489 Pa.
The latent heat of ice meting = 5.85 kJ/mol
Normal phase change occurred at constant temperature but here pressure is changing because here freezing is occurred in supercooled water.
Maxwell Relation:-
We get Gibbs free energy
dG = -sDτ+vdP, where s is the entropy
Now at isothermal condition, dτ=0
dG = 0 + vdP = vdP
Assumint the vapour to behave as ideal gas,
v=RT/P
dG = (RT/P)dP
Now in regrating ora get got change of molar Gibbs free energy
⇒ ∫dG = ΔG = RT ln(P₂/P₁)
where P₁ = final pressure = 489 Pa
P₂ = 475 Pa
T = (273-3) k = 270 k
Since 1 atm = 101.389 kPa
Therefore, ΔG = 0.0821×270×ln (475/489)
= -65.246 J Mol⁻¹
Hence, the value of g is -65.246 j Mol⁻¹.
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