Solubility is the ability of the solute to form a complex with solvent to produce a solution. 12.30 is the pH of the saturated solution of triethylamine.
The pH of the solution is the hydrogen or the hydronium ion potential dissolved in the water.
Given,
Solubility of triethylamine = 68.6gL
Molar mass = 101.19 gm/mol
NAse ionization constant = 6. 0×10−4
The concentration of the solution will be:
68.6gL ÷ 101.19 gmol = 0.678M
The equation for the base ionization is shown as:
B+ H₂O ⇄ BH⁺ + OH⁻
Here, base (B) and conjugate acid (BH⁺). If the initial concentration of base decreases as −x and the concentration of BH⁺ and OH⁻ increase by x then,
The final concentrations are:
[B] =0.678−x,
[BH⁺] =x
[OH⁻] =x
The base ionization constant:
Kb = [BH⁺][OH⁻] / [B]
6.0×10⁻⁴ = x² 0.678
Solving further for x:
x = √(6.0×10⁻⁴)(0.678)
= 2.02×10⁻² M
The pOH is calculated as:
pOH = −log [OH⁻]
= − log(2.02×10⁻²)
= 1.70
Solving for the pH:
pH = pKw − pOH
pH = 14.00 − 1.70
= 12.30
Therefore, 12.30 is the pH of the saturated solution of triethylamine in water.
Learn more about pH here:
https://brainly.com/question/4144379
#SPJ4