Triethylamine, n(c2h5)3, has a solubility of 68. 6gl, a molar mass of 101. 19gmol, and a base-ionization constant kb=6. 0×10−4. What is the ph of a saturated solution of triethylamine in water?

Respuesta :

Solubility is the ability of the solute to form a complex with solvent to produce a solution. 12.30 is the pH of the saturated solution of triethylamine.

What is pH?

The pH of the solution is the hydrogen or the hydronium ion potential dissolved in the water.

Given,

Solubility of triethylamine = 68.6gL

Molar mass = 101.19 gm/mol

NAse ionization constant = 6. 0×10−4

The concentration of the solution will be:

68.6gL ÷ 101.19 gmol = 0.678M

The equation for the base ionization is shown as:

B+ H₂O ⇄ BH⁺ + OH⁻

Here, base (B) and conjugate acid (BH⁺). If the initial concentration of base decreases as −x and the concentration of BH⁺ and OH⁻ increase by x then,

The final concentrations are:

[B] =0.678−x,

[BH⁺] =x

[OH⁻] =x

The base ionization constant:

Kb = [BH⁺][OH⁻] / [B]

6.0×10⁻⁴ = x² 0.678

Solving further for x:

x = √(6.0×10⁻⁴)(0.678)

= 2.02×10⁻² M

The pOH is calculated as:

pOH = −log [OH⁻]

= − log(2.02×10⁻²)

= 1.70

Solving for the pH:

pH = pKw − pOH

pH = 14.00 − 1.70

= 12.30

Therefore, 12.30 is the pH of the saturated solution of triethylamine in water.

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