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Malonic acid is a diprotic acid used in the production of pharmaceuticals. a 0.965 g sample of malonic acid requires 45.91 ml of 0.404 m lioh to be neutralized. determine the molar mass (g/mol) for malonic acid

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The molar mass of the malonic acid given the data from the question is 104.3 g/mol

How to determine the mole of LiOH

We'll begin by calculating the number of mole in 45.91 mL of 0.404 M LiOH. This can be obtained as follow:

  • Volume = 45.91 mL = 45.91 / 1000 = 0.04591 L
  • Molarity of LiOH = 0.404 M
  • Mole of LiOH =?

Mole = Molarity x Volume

Mole of LiOH = 0.404  × 0.04591

Mole of LiOH = 0.0185 mole

How to determine mole of malonic acid

Malonic acid => H₂X

H₂X + 2LiOH —> Li₂X + 2H₂O

From the balanced equation above,

2 moles of LiOH reacted with 1 mole of H₂X.

Therefore,

0.0185 mole of LiOH will react with = 0.0185 / 2 = 0.00925 mole of H₂X.

How to determine the molar mass of malonic acid

Malonic acid => H₂X

  • Mole of H₂X = 0.00925 mole
  • Mass of H₂X = 0.965 g
  • Molar mass of H₂X =?

Molar mass = mass / mole

Molar mass of H₂X = 0.965 / 0.00925

Molar mass of H₂X = 104.3 g/mol

Thus, the molar mass of the malonic acid, H₂X is 104.3 g/mol

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