Answer:
The arrow is at a height of 500 feet at time t = 2.35 seconds.
Step-by-step explanation:
It is given that,
An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s
The projectile formula is given by :
[tex]h=-16t^{2} +vot[/tex]
We need to find the time(s), in seconds, the arrow is at a height of 500 ft.
So,
[tex]-16t^{2} +250t=500[/tex]
On solving the above quadratic equation, we get the value of t as, t = 2.35 seconds
So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.
Answer:
An arrow is shot vertically upward at a rate of 210 feet per second. Use the projectile formula
h = −16t2 + v0t
to determine at what time t (in seconds) the height of the arrow will be 300 feet.
Step-by-step explanation:
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