The ksp of CaCrO₄ is 7.13 × 10⁻⁴.
The ksp can be defined as the solubility constant of a solid sample in the aqueous solution.
The molarity of CaCrO₄ in the solution is given as:
Molarity = mass/molar mass × 1000/Volume (mL)
Molarity = 0.649 g/ 156 g/mol × 1000 / 156 mL
Molarity = 0.0267 mol/L
The solubility of CaCrO₄ is given as:
[CaCrO₄] = [Ca²⁺] [CrO₄²⁻]
ksp is given as:
ksp = Molarity of [Ca²⁺] × Molarity of [CrO₄²⁻]
ksp = s × s
ksp = s²
Substituting the values:
ksp = (0.0267)²
ksp = 7.13 × 10⁻⁴
Thus, the ksp of CaCrO₄ is 7.13 × 10⁻⁴.
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