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In a certain state, a survey of 600 workers showed that 35% belonged to a union. Find the 95% confidence interval of true proportion of workers who belong to a union. Question 10 options: (34.9618, 35.0382) (0.29, 0.41) (0.3118, 0.3882) 210 (0.0396, 0.0771)

Respuesta :

The 95% confidence interval of true proportion of workers who belong to a union is; CI = (0.29, 0.41)

How to find the Confidence Interval?

We are given;

Sample size; n = 600

Sample proportion; p = 35% = 0.35

Formula for confidence interval is;

CI = p ± z√(pq/n)

The z-score at 95% confidence interval is z = 1.96

Thus;

CI = 0.35 ± 1.96√(0.35(1 - 0.35)/600)

CI = (0.29, 0.41)

Thus, the 95% confidence interval of true proportion of workers who belong to a union is; CI = (0.29, 0.41)

Read more about Confidence Interval at; https://brainly.com/question/17097944

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