In a football tournament, each team plays exactly 19 games.
Teams get 3 points for every win and 1 point for every tie.
At the end of the tournament, team Olympus got a total of 28 points.
From the following options, how many times could team Olympus have tied?

Respuesta :

Answer:16  ties

Step-by-step explanation:

there is 19 games if they tied 16 then that 16 points so 28 - 16= 12  

then 4 games left so 4 times 3 is 12

At the end of the tournament, team Olympus have tied for 13,10,7,4,1 times

What is inequality?

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

According to question

In a football tournament, each team plays exactly 19 games.

Points for every win (w) = 3

Points for every tie (t)= 1

Points for every loose = 0

Olympus got a total of 28 points

i.e  3w + t = 28 ---------(1)

And each team plays  19 games

T + W  ≤  19 --------------(2)

and T , W ≥ 0

from equation (1) and (2)

=> 2W  ≥  9

=> W ≥ 4.5  

( match can be won in integers only )

=> W  ≥  5  

W       T        Loose

5        13           1

6        10           3

7         7            5

8         4            7

9          1            9    

Hence, Olympus have tied for 13,10,7,4,1 times

To know more about Inequality here :

https://brainly.com/question/15137133

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