20.927 g of mass of 4.0 L of oxygen at 4.0 ATM and 25 degrees celcius.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Volume of oxygen [tex]O_2[/tex] would be 4 L.
Pressure (P) = 4.0 atm
Temperature (T) = 298 K
Universal gas constant (R) = 0.0821 L.atm/mol.K
Molecular mass of oxygen = 32 g/mol
Mass can be calculated by using the Ideal gas equation which is :
PV = nRT (Ideal gas equation)
On rearranging the above formula we will get :
[tex]\frac{PV}{RT} = \frac{Mass}{Molar\;mass}[/tex]
[tex]\frac{4.0 atm X 4 L}{0.0821 L.atm/mol.K X 298 K} = \frac{Mass}{Molar\;mass}[/tex]
Mass = 20.927 g
Hence, 20.927 g of mass of 4.0 L of oxygen at 4.0 ATM and 25 degrees celcius.
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