The volume that 4.00 moles of H₂ will occupy at the same temperature and pressure is 44.8 L
From the question, we are to determine the volume that 4.00 moles of H₂ will occupy
From the Ideal gas equation, we have that
PV = nRT
Where P is the pressure
V is the volume
n is the number of mole
R is the gas constant
and T is the temperature
Keeping the temperature and pressure are kept constant alongside the gas constant
Then,
V = kn
Then, we can write that
[tex]\frac{V }{n } = k[/tex]
[tex]\frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} }[/tex]
Where V₁ is the initial volume
n₁ is the initial number of mole
V₂ is the final volume
n₂ is the final number of mole
Then,
From the given information,
V₁ = 11.2 L
n₁ = 1 mole
n₂ = 4.00 moles
[tex]\frac{11.2}{1}=\frac{V_{2} }{4.00}[/tex]
∴ V₂ = 4.00 × 11.2
V₂ = 44.8 L
Hence, the volume that 4.00 moles of H₂ will occupy at the same temperature and pressure is 44.8 L
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