Aaron has a dozen eggs in a carton. Three of the eggs are raw and the rest are hardboiled. Aaron
takes out one egg at random and cracks it. Ne then takes out another egg and cracks it.
What is the probability that the first egg cracked was hardboiled and the second was raw?

Respuesta :

The probability that the first egg is hardboiled and the second is raw is:

p = 9/44 = 0.205

How to find the probability?

We know that there are 12 eggs, 3 are raw and the other 9 are hardboiled.

The probability that the first egg is hardboiled is equal to the quotient between the number of hardboiled eggs and the total number of eggs:

P = 9/12

Then for the second egg, it must be raw, the probability can be obtained in the same way, but because we already got a hardboiled egg, now there is a total of 11 eggs, so we get:

Q = 3/11

The joint probability is the product of the individual probabilities, so we get:

probability = (9/12)*(3/11) = 9/44 = 0.205

If you want to learn more about probability:

https://brainly.com/question/25870256

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