Answer:
A) [tex]0.13[/tex]
Step-by-step explanation:
If a function [tex]f(x)[/tex] is continuous over the interval [tex][a,b][/tex], then the average rate of change over that interval is [tex]\displaystyle \frac{f(b)-f(a)}{b-a}[/tex]:
[tex]\displaystyle \frac{f(b)-f(a)}{b-a}\\\\\frac{f(7)-f(2)}{7-2}\\ \\\frac{1.91-1.26}{5}\\ \\\frac{0.65}{5}\\ \\0.13[/tex]
Thus, the average rate of change over the interval [tex][2,7][/tex] to the nearest hundredth is [tex]0.13[/tex].
