Answer:
[tex]x=\frac{5}{2}[/tex] or x= -4
Step-by-step explanation:
To solve the quadratic equation, start by factorizing it.
[tex]2x^{2} +3x-20=0[/tex]
(2x -5)(x +4)= 0
Since the equation equals to zero, either one of its factor, i.e. (2x -5) or (x +4), can be equal to zero.
2x -5= 0 or x +4= 0
Solve for x:
2x= 5 or x= -4
[tex]\bf{x=\frac{5}{2}}[/tex]
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Alternatively, the quadratic formula can be used to solve the equation.
[tex]\boxed{x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a} }[/tex]
This is especially useful when the quadratic equation cannot be factorized. To use the formula, ensure that the equation is in the form of [tex]ax^{2} +bx +c=0[/tex].
Additional:
For an example on solving quadratic equations using the quadratic formula, do check out the following!
- https://brainly.com/question/27739892
