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On an ice skating rink, a girl of mass 50 kg stands stationary, face to face with a boy of mass 80 kg. the children push off of one another, and the boy moves away with a velocity of 3 m/s. what is the final velocity of the girl? –1.9 m/s 1.9 m/s –4.8 m/s 4.8 m/s

Respuesta :

onyebuchinnaji

The final velocity of the girl after the collision is determined as -4.8 m/s.

Final velocity of the girl

The final velocity of the girl is determined from the principle of conservation of linear momentum.

m1u1 + m2u2 = m1v1 + m2v2

50(0) + 80(0) = 50(v1) + 80(3)

0 = 50v1 + 240

50v1 = -240

v1 = -240/50

v1 = -4.8 m/s

Thus, the final velocity of the girl after the collision is determined as -4.8 m/s.

Learn more about conservation of linear momentum here:  https://brainly.com/question/7538238

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