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The area of the given triangle will be [tex]\dfrac{5\sqrt{2}}{2}[/tex]
Triangle is a shape made of three sides in a two-dimensional plane. the sum of the three angles is 180 degrees.
Given points of the triangle are:-
( -6,5 ) (-5,3 ) and (-8, 2)
Now we will apply the area formula for the triangle:-
[tex]A = \dfrac{1}{2} \times B\times H[/tex]
The base will be = [tex]\sqrt{(-5++8)^2+(3-2)^2)}=\sqrt{9+1}=\sqrt{10}}[/tex]
The Height will be = [tex]\sqrt{(-5+6)^2+(5-3)^2}=\sqrt5[/tex]
The area will be calculated as:-
[tex]A =\dfrac{1}{2}\times \sqrt{10}\times \sqrt{5}=\dfrac{5\sqrt{2}}{2}}[/tex]
Therefore the area of the given triangle will be [tex]\dfrac{5\sqrt{2}}{2}[/tex]
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