The LCD of the rational equation [tex]-\frac{3}{x + 2} + \frac{5x}{x - 1} = \frac{x + 2}{x^2 -3x + 2}[/tex] is (x + 2) (x -1)(x - 2)
How to determine the LCD?
The rational equation is given as:
[tex]-\frac{3}{x + 2} + \frac{5x}{x - 1} = \frac{x + 2}{x^2 -3x + 2}[/tex]
Factorize the quadratic denominator
[tex]-\frac{3}{x + 2} + \frac{5x}{x - 1} = \frac{x + 2}{(x -1)(x - 2)}[/tex]
Write out the denominators
(x + 2), (x - 1) and (x -1)(x - 2)
Remove the repetition
(x + 2) (x -1)(x - 2)
Hence, the LCD of the rational equation is (x + 2) (x -1)(x - 2)
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