There are 142506 different selections of twenty-five pastries
The given parameters are:
The number of different selections is calculated using:
[tex]C(n + r - 1,r) = \frac{(n + r - 1)!}{r!(n - 1)!}[/tex]
The above formula is used because repetitions are allowed.
So, we have:
[tex]C(6 + 25 - 1,25) = \frac{(6 + 25 - 1)!}{25!(6 - 1)!}[/tex]
Evaluate the sum and difference
[tex]C(30,25) = \frac{30!}{25!5!}[/tex]
Evaluate the expression
C(30,25) = 142506
Hence, there are 142506 different selections of twenty-five pastries
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