Answer:
(6x² +4x -20)/(x² +x -3) cm
Step-by-step explanation:
The perimeter of a rectangle is twice the sum of its length and width. Here, length and width are rational functions. The same relation to perimeter applies.
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[tex]P = 2(L+W)\\\\P=2\left(\dfrac{2x^2 +3x-5}{x^2+x-3}+\dfrac{x^2-x-5}{x^2+x-3}\right)\qquad\text{use given values for $L$ and $W$}\\\\P=2\left(\dfrac{2x^2+3x-5+x^2-x-5}{x^2+x-3}\right)=\dfrac{2(3x^2 +2x-10)}{x^2+x-3}\\\\P=\dfrac{6x^2+4x-20}{x^2+x-3}\\\\\underline{\ \qquad}\\\\\textsf{It would take $\dfrac{6x^2+4x-20}{x^2+x-3}$ cm of ribbon to go around the package.}[/tex]
