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Solvex²= 12x-15 by completing the square. Which is the solution set of the equation?
-6- √51, -6 + √51)
1-6-√21, −6+ √21}
(6-√51, 6+ √51)
16-√21, 6+ √21}

Respuesta :

swaleha2004

Answer

B

Step-by-step explanation:

MrRoyal

The solution to the equation by completing the square is (6 - √21, 6 + √21)

How to complete the square?

The equation is given as:

x²= 12x-15

Rewrite as:

x² -12x = -15

Take the coefficient of x

k = -12

Divide by 2

k/2 = -6

Square both sides

k/4 = 36

Add 36 to both sides of x² -12x = -15

x² -12x + 36 = -15 + 36

Evaluate the sum

x² -12x + 36 = 21

Express the equation as a perfect square

(x - 6)² = 21

Take the square root of both sides

x - 6 = ±√21

Add 6 to both sides

x = 6 ± √21

Split

x = (6 - √21, 6 + √21)

Hence, the solution to the equation by completing the square is (6 - √21, 6 + √21)

Read more about solution set at:

https://brainly.com/question/25275758

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