The 15th term of the sequence is 2390
Given the recursive formula of the sequence given;
[tex]a_n=a_{n-1}-200[/tex]
Given the following parameters
Common difference = -200
a1. = 10
[tex]a_{15} =a_{14} -200[/tex]
Determine the 14th term
T14 = 10+(14-1)(-200)
T14 = 10+(-2600)
T14 = 2590
Substitute
a15 = 2590 - 200
a15 = 2390
Hence the 15th term of the sequence is 2390
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