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Suppose a piece of sodium metal gains 2.05 g of mass after being exposed to air. assume that this gain can be attributed to its reaction with oxygen.
(a) what mass of o2 reacted with the na? (b) what mass of na reacted? (c) what mass of na2o formed?

Respuesta :

mickymike92

Based on the reaction equation:

  • Mass of oxygen added to sodium = 2.05 g
  • Mass of sodium reacted = 5.75 g of sodium
  • Mass of sodium oxide formed = 7.75 g

What is reaction between sodium metal and oxygen?

The reaction between sodium metal and oxygen is an oxidation reaction.

The equation of the reaction is given below:

  • [tex]4Na(s) + O_{2} (g) \rightarrow 2Na_{2}O (s)[/tex]

Based on the equation of the reaction, 4 moles of sodium metal reacts with one mole of oxygen to produce 2 moles of sodium oxide.

Mass of oxygen added to sodium = 2.05 g

2.0 g of oxygen = 2/32 moles = 0.0625 moles

Moles of sodium reacted = 0.0625 * 4 = 0.25 moles

Mass of sodium reacted = 0.25 * 23 g = 5.75 g of sodium

Mass of sodium oxide formed = 5.75 + 2.05 = 7.75 g

Learn  more about oxidation reaction at: https://brainly.com/question/16771450

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