Reduction of 9-fluorenone: objective of this lab was to reduce 9-fluorenone (a ketone), to 9-fluorenol (an alcohol) using sodium borohydride as the reducing agent. experimental data: 9-fluorenone: mw 180.20 g/mol mass used 0.6 grams methanol: mw 32.04 g/mol volume used: 6ml density: 0.792 nabh4: mw 37.83 g/mol mass used 0.05 grams 9-fluorenol: mw 182.22 g/mol balanced equation for the reaction is: 4c13h8o nabh4 4ch3oh --> 4c13h10o nab(och3)4 calculate the potential yield (in grams) of 9-fluorenol for 9-fluorenone, methanol and nabh4. from these potential yields identify the limiting reagent and theoretical yield.

Out of the three reactants, [tex]NaBH_4[/tex] acts as a reducing agent only and hence the reaction can occur only when [tex]NaBH_4[/tex] is present in relatively much smaller amounts. But the yield of the product,9-fluorenol, is not governed by its quantity.

Theoretically, when equimolar amounts of reactants ( 9-fluorenone and methanol ) are taken for reaction in presence of [tex]NaBH_4[/tex] an equivalent quantity of product, 9- fluorine is obtained, as inspected in the above stoichiometric relations. But practically we have used a lesser number of moles of 9-fluorenone than theoretically needed, hence in this case it should serve as the limiting reagent.

9- fluorenone, methanol & [tex]NaBH_4[/tex] are the reactants, while the product 9-fluorenol would be obtained = 0.0033 moles

This would represent the theoretical yield of the product 9-fluorenone, as we have used an excess of methanol thus facilitating the reaction to go to completion.

Hence, 9-fluorenone is a limiting reagent.

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