Please help me do the equation and figure out the right solution. I am supposed to be correcting the one in the picture.

Answer:
The correct answer is if you want no roots in the denominator, the correct answer is [tex]\frac{2x}{y}[/tex]* [tex]\sqrt[3]{2y^{2} }[/tex]
Step-by-step explanation:
The mistake is that you can't take a cube root of a square at step 3 when [tex]y^{2}[/tex] is taken out.