You are driving through town at 11.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.2 m/s?


The distance moved by the vehicle on after brakes is 18.91 m.
The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Speed s = distance d / time t
You are driving through town at 11.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.2 m/s.
The final velocity will be zero, when brakes are applied.
Using the third equation of motion,
v² -u² =2as
0² - 11² = 2x (-3.2) s
s = 18.91 m
Thus, the distance moves on applying brakes, is 18.91 m.
When half of the distance is traveled, the speed will be
v² -u² =2as
0² - u² = 2x (-3.2) (18.91/2)
u = 7.78 m/s
Thus, the speed will be 7.78 m/s i.e greater than 5.5 m/s.
Learn more about speed.
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