It is Given that f(x) = log₂ (x + 4), so the value of f(3) is log₂ (7) or 2.807.
When you raise a number with an exponent, there comes a result.
Let's say you get
a^b = c
Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows
[tex]b = \log_a(c)[/tex]
'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'
Given ;
f(x) = log₂ (x + 4)
we need to find f(3)
substitute x = 3 in f(x)
f(x) = log₂ (x + 4)
f(3) = log₂ (3 + 4)
f(3) = log₂ (7)
Hence, f(3) = 2.807
Learn more about logarithm here:
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