Respuesta :

Apply Pythagorean theorem

[tex]\\ \tt{:}\longrightarrow P^2=H^2-B^2[/tex]

[tex]\\ \tt{:}\longrightarrow P^2=100^2-96^2[/tex]

[tex]\\ \tt{:}\longrightarrow P^2=28^2[/tex]

[tex]\\ \tt{:}\longrightarrow x=28[/tex]

Option A

Answer:

x = 28

Step-by-step explanation:

The tangent of a circle is always perpendicular (at a right angle) to the radius.

As the triangle ABC is a right triangle, we can use Pythagoras Theorem to find x.

Pythagoras Theorem

[tex]\sf a^2+b^2=c^2[/tex]

where:

  • a and b are the legs of the right triangle
  • c is the hypotenuse (longest side) of the right triangle

From inspection of the triangle ABC:

  • a = BC = x
  • b = AB = 96
  • c = AC = 100

Substitute the values into the formula and solve for x:

[tex]\implies \sf x^2+96^2=100^2[/tex]

[tex]\implies \sf x^2=100^2-96^2[/tex]

[tex]\implies \sf x^2=784[/tex]

[tex]\implies \sf \sqrt{ x^2}=\sqrt{784}[/tex]

[tex]\implies \sf x=\pm28[/tex]

Therefore, as length is positive, the value of x is 28.

Learn more about Pythagoras Theorem here:

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