There is no solution for b.
The rule for operations done in exponents are
(a) [tex]a^m*a^n=a^{m+n}[/tex]
(b) [tex]a^m/a^n=a^{m-n}[/tex]
(c)[tex](1/a)^m=a^{-m}[/tex]
Given the expression (one-twelfth) superscript negative 2 b baseline times 12 superscript negative 2 b+2 baseline = 12
the expression (one-twelfth) superscript negative 2 b simplifies that [tex](1/12)^{-2b}[/tex]
12 superscript negative 2b+ 2 simplifies that [tex]12^{-2b+2}[/tex]
so the final expression (one-twelfth) superscript negative 2 b baseline times 12 superscript negative 2 b+2 baseline = 12 will be
[tex](1/12)^{-2b}[/tex] * [tex]12^{-2b+2}[/tex] =12
⇒[tex]12^{-(-2b)}\\[/tex] * [tex]12^{-2b+2}[/tex] =12
⇒[tex]12^{2b[/tex] * [tex]12^{-2b+2}[/tex] =12
⇒[tex]12^{2b-2b+2}[/tex]=12¹
equating the exponts of the both sides
⇒2b-2b+2=1
⇒2=1 (not accepted because un-logic condition)
Therefore there is no solution.
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