rdesmangles
contestada

In a group of twelve people, four had been selected for a transfer. If two of the twelve are selected, what is the probability that both of those selected are selected for a transfer?
about 5%
about 9%
about 12%
about 15%

Respuesta :

youreuphoria5

Answer:

9%

Step-by-step explanation:

Probability of the first person being selected is 4/12 and the probability of the second person being selected is 3/11

The probability of both is:

4/12 x 3/11

= 1/11 which is 9%

konrad509

[tex]\displaystyle\\|\Omega|=\binom{12}{2}=\dfrac{12!}{2!10!}=\dfrac{11\cdot12}{2}=66\\|A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\P(A)=\dfrac{6}{66}=\dfrac{1}{11}\approx9\%[/tex]

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