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Question 10 of 32
A sample of 2 mol of diatomic gas is measured to have a temperature of 323
K. If the mass of the gas is 0.032 kg, what is the approximate average speed
of the molecules in the gas? (Recall that the equation for kinetic energy due
1
3
to translation in a gas is KEtranslational=mv²=nRT, and R= 8.31 J/(mol-
K).)
2
2

Respuesta :

Eduard22sly

The approximate average speed of the molecules in the gas is 410 m/s

Data obtained from the question

  • Number of mole (n) = 2 moles
  • Temperature (T) = 323 K
  • Mass (m) = 0.032 Kg
  • Gas constant (R) = 8.31 J/Kmol
  • Speed (v) =?

How to determine the speed

mv² = nRT

Divide both side by m

v²= nRT / m

Take the square root of both sides

v = √(nRT / m)

v = √(2 × 8.31 × 323 / 0.032)

v = 410 m/s

Learn more about ideal gas equation:

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